Canadian Society for Medical Laboratory Science (CSMLS) Practice Exam 2025 - Free Medical Laboratory Science Practice Questions and Study Guide

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What is the dilution when 0.1 mL of a sample is added to 2.9 mL of distilled water?

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To determine the dilution achieved when 0.1 mL of a sample is added to 2.9 mL of distilled water, we first need to calculate the total final volume of the solution after mixing.

The total volume is the sum of the volume of the sample and the volume of the water added. In this case:

- Volume of the sample = 0.1 mL

- Volume of water = 2.9 mL

Adding these together gives us a total volume of 3.0 mL.

Now, the dilution factor can be expressed as the ratio of the final volume to the volume of the sample. This can be calculated as follows:

- Dilution factor = Total volume / Volume of the sample = 3.0 mL / 0.1 mL = 30.

This means the sample is diluted to 30 times its original concentration. For expressing this in terms of its parts, we calculate the dilution as the ratio of the volume of solvent (water) to the volume of the sample.

The volume of the solvent is 2.9 mL, and the volume of the sample is 0.1 mL, leading to:

- Volume of solvent/Volume of

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1:29

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